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The reagent used in Hoffmann’s mustard oil reaction is

$\begin {array} {1 1} (A)\;\text{Mustard oil and primary amine} & \quad (B)\;\text{$CS_2 $ and aniline in $HgCl_2$} \\ (C)\;\text{Nitrobenzene and $CS_2$} & \quad (D)\;\text{Sand RNC} \end {array}$

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$\text{ethyl amine} \: \: \: \: \: \text{ carbon dislphite } \: \: \: \: \: \text{dithioethylcarbamic acid}$
ethyl isothiocyanate (mustard oil)
Ans : (B)
answered Mar 21, 2014 by thanvigandhi_1

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