\[(a)\;13 \% \quad (b)\;12 \%\quad (c)\;10 \% \quad (d)\;1.0\%\]

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$P=\large\frac{a^3b^2}{(\sqrt {cd})}$

$\large\frac{\Delta p}{p}$$=3 \large\frac{\Delta b}{b}$$+2 \large\frac{\Delta b}{b}+\frac{1}{2} \frac{\Delta c}{c}+\frac{1}{2} \frac{\Delta d}{d}$

$\%$ error in $P=3 \%$ error in a+$2 \%$ error in b+$\large\frac{1}{2} \%$ error in c+$\large\frac{1}{2} \%$ error in d

$\qquad\qquad=3 \%+6 \%+2 \%+1 \%$

$\qquad\qquad=12 \%$

Hence the percentage of error in calculation of $P$ is $12\%$

Hence b is the correct answer.

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