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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class12  >>  Electromagnetic Induction
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A coil of inductance $84\;mH$ and resistance $8 \Omega$ is connected to $12 V$ battery. The current in the coil is 1 A at approximately

$(a)\;5\;ms \\ (b)\;1\;ms \\(c)\;500\;ms \\(d)\;10\;ms $

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Time constant
$T= \large\frac{L}{R}$
$\quad= \large\frac{8.4}{6 \Omega}$$mH$
$\quad= 1.4 \;mH$
Current in the circuit at time t is $I= \large\frac{V}{R}$$(1-e^{-t/T})$
$1A= \bigg( \large\frac{12 V}{6 \Omega}\bigg)$$(1-e^{-t/1.4})$
$-t/1.4=ln \bigg(\large\frac{1}{2}\bigg)$
$t= 1.4 \times 0.693$
$\qquad= 0.97\;ms$
Hence b option is correct.
answered Mar 24, 2014 by meena.p

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