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In the given circuit shown : $L= 200\;mH;$ Emp of battery $E= 12 V$ $R_1=R_2=2 \Omega$ the internal resistance of battrey is negligible . The potential drop across the inductance L after time t.

$(a)\;6\;e^{-5t}\;V \\ (b)\;\frac{12}{t} e^{-3t} \;V \\(c)\;6 [1-e^{t/.2}]V \\(d)\;12\;e^{-10\;t}V $

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