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Coefficient of real expansion of mercury is $\;0.18\times 10^{-3}/^{0}C\;$ . If the density of mercury at $\;0^{0}C\;$ is $\;13.6\;gm/C.C\;$ , then is density at 473 K will be


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Answer : $\;13.11\;g/C.C$
Explanation :
$\rho = \large\frac{\rho_{0}}{(1+r_{0}t)}$
$=\large\frac{13.6}{1+0.18\times (200^{0}C)}$
answered Mar 24, 2014 by yamini.v

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