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When 52 g of liquid in a vessel is heated from $\;0^{0}C\;$ to $\;100^{0}C\;$ 2 g of liquid is expelled . If 104 g of liquid is taken in a vessel made of same matenal how much of liquid is expelled on heating from $\;0^{0}C\;$ to $\;100^{0}C\;$ ?


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Answer : $\;4\;g$
Explanation :
$r= \large\frac{weight\;of\;liquid\;expelled}{weight\;of\;remaining\;liquid \times \bigtriangleup t}$
$\large\frac{2}{50 \times 100} = \large\frac{x}{(104-x)\;.100}$
answered Mar 24, 2014 by yamini.v

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