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Evaluate : $ \begin{bmatrix} a+ib & c+id \\ -c+id & a-ib \end{bmatrix} $

1 Answer

=(α+iβ)(α-iβ)-(c-iβ) (c+iβ) Remember i² =-1 So, forget i Then, using algebra formula (a+b)(a-b) =a²+b² We will get as below, α²+β²+c²+β² (ans)
answered Nov 22, 2017 by rabindrasinghrouth
 
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