Ask Questions, Get Answers

Want to ask us a question? Click here
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Thermodynamics
0 votes

The temperature gradient in a rod 0.5 m long is 80 c/m . The temperature of the hot end of the rod is $\;30^{0}C\;$. Then the temperature of the cooler and is


Can you answer this question?

1 Answer

0 votes
Answer : $\;-10^{0}C$
Explanation :
$\large\frac{T_{H}-T_{C}}{L}=\large\frac{\bigtriangleup T}{L}$
$80 = \large\frac{T_{H}-T_{L}}{0.5} $
$T_{L}=T_{H} - 40 = -10^{0}C$
answered Mar 24, 2014 by yamini.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App