$(a)\;5 \; \Omega,10\;\Omega \\ (b)\;5\;\Omega,5 \sqrt 3 \Omega \\(c)\;3 \sqrt 3 \Omega , 10 \;\Omega \\(d)\;5 \sqrt {3} \Omega, 2 \sqrt 3 \Omega $

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$Z= \sqrt {R^2+X_L^2}$

$E= 10\;V$ and $I= 1A$

$\therefore Z=\large\frac{E}{I}=\frac{10}{1} $$=10 \; \Omega$

$\large\frac{X_L}{R}$$= \tan \phi=\tan \large\frac{\pi}{3} $$=\sqrt 3$

$X_L=\sqrt 3 R$

$Z= \sqrt {R^2+(\sqrt 3R)^2}=10$

=> $2R= 10$

$R= 5 \Omega$

$X_L =\sqrt 3 R =\sqrt 3 \times 5$

$\qquad= 5 \sqrt 3 \Omega$

Hence b is the correct answer.

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