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What volume of $CO_2$ will be liberated at NTP if 1.2g of carbon is burnt in excess of oxygen?

$\begin{array}{1 1}(a)\;1.12litre&(b)\;2.24litre\\(c)\;22.4litre&(d)\;11.2litre\end{array}$

$C+O_2\rightarrow CO_2$
$\therefore$ 12g C liberates =22.4litre of $CO_2$
$\therefore$ 1.2g of C liberate =$\large\frac{22.4}{12}$$\times 1.2$
$\Rightarrow 2.24$litre of $CO_2$
Hence (b) is the correct answer.