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Questions  >>  JEEMAIN and NEET  >>  Physics  >>  Class12  >>  Alternating Current
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The equation of AC voltage is $E=220\; \sin (wt+\large\frac{\pi}{6})$ and AC current is $I= 10 \sin (wt+\large\frac{\pi}{6})$ The average power dissipated is

$(a)\;150\;W \\ (b)\;550\;W \\(c)\;250\;W \\(d)\;50\;W $

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