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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Thermodynamics
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The maximum emission wavelength at temperature 2000 K is $\;4 \mu m\;$ . The maximum wavelength corresponding to temperature 2400 K will be

$(a)\;3.33 \times 10^{-6} \;m\qquad(b)\;1\;m\qquad(c)\;10^{-6}\;m\qquad(d)\;0.66 \times 10^{-6}\;m$

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Answer : $\; 3.33 \times 10^{-6} \;m$
Explanation :
$\lambda m T = constant\;\;$ (wein's displacement)
$4 \mu m \times 2000 = 2400 \times \lambda_{m}$
$\lambda_{m}=3.33 \times 10^{-6}\;m$
answered Mar 26, 2014 by yamini.v

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