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112.0ml of $NO_2$ at STP was liquefied,the density of the liquid being $1.15gmL^{-1}$.Calculate the volume and the number of molecules in the liquid $NO_2$.

$\begin{array}{1 1}(a)\;0.10mL\;and\;3.01\times 10^{22}\\ (b)\;0.20mL\;and\;3.01\times 10^{21} \\(c)\;0.20mL\;and\;6.02\times 10^{23}\\(d)\;0.10mL\;and\;6.02\times 10^{21}\end{array} $

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At STP 22400ml of $NO_2$=46g of $NO_2$
$112.0$ml of $NO_2=\large\frac{112.0mL\times 46.0g}{22400mL}$$=0.23$g
$V_{NO_2}=\large\frac{Mass}{Density}=\frac{0.23}{1.15gmL^{-1}}$$=0.20mL$
Number of molecules =$\large\frac{0.23}{46}$$\times 6.02\times 10^{23}$
$\Rightarrow 3.01\times 10^{21}$
Hence (b) is the correct answer.
answered Mar 25, 2014 by sreemathi.v
 

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