logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

'M' g of an element gave 'N' g of oxide.Equivalent weight of the element is

$\begin{array}{1 1}(a)\;\large\frac{M+N}{M}\normalsize \times 8& (b)\;\large\frac{M}{N+M}\normalsize\times 8 \\(c)\;(N-M)\times 8&(d)\;\large\frac{M}{N-M}\normalsize\times 8\end{array} $

Can you answer this question?
 
 

1 Answer

0 votes
The weight of element =M g
Weight of oxide =N g
$\therefore$ weight of oxygen =(N-M)g
(N-M)g of oxygen combines with Mg of elements.
8g of oxygen combines with $\large\frac{M}{(N-M)}$$\times 8g$ of element.
Hence (d) is the correct answer.
answered Mar 25, 2014 by sreemathi.v
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...