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'M' g of an element gave 'N' g of oxide.Equivalent weight of the element is

$\begin{array}{1 1}(a)\;\large\frac{M+N}{M}\normalsize \times 8& (b)\;\large\frac{M}{N+M}\normalsize\times 8 \\(c)\;(N-M)\times 8&(d)\;\large\frac{M}{N-M}\normalsize\times 8\end{array} $

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The weight of element =M g
Weight of oxide =N g
$\therefore$ weight of oxygen =(N-M)g
(N-M)g of oxygen combines with Mg of elements.
8g of oxygen combines with $\large\frac{M}{(N-M)}$$\times 8g$ of element.
Hence (d) is the correct answer.
answered Mar 25, 2014 by sreemathi.v

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