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Two grams sulphur is completely burnt in oxygen to form $SO_2$.In this reaction.What is the volume (in litres) of oxygen consumed at S.T.P?(At.mass of S and O are 32 and 16 respectively.)

$\begin{array}{1 1}(a)\;\large\frac{16}{22.414}& (b)\;\large\frac{22.414}{16} \\(c)\;\large\frac{22.414}{32}&(d)\;\large\frac{32}{22.414}\end{array} $

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$S+O_2\rightarrow SO_2$
32g S require $O_2$ at STP=22.414L
2g S require $O_2$ at STP=$\large\frac{22.414}{32}$$\times2L$
$\Rightarrow \large\frac{22.414}{16}$L
Hence (b) is the correct answer.
answered Mar 25, 2014 by sreemathi.v
 

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