$(a)\;30\;mv \\(b)\;15\;mv \\ (c)\;3.0\;mv \\ (d)\;1.5\;mv$

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Induced $emf = Blv \sin 30^{\circ}$

$\phi = 5 \times 10^{-6} \;Wb$

$A= (2\;cm)^2= 4 \times 10^{-4}m^2$

$B=\large\frac{\phi}{\pi}$$=1.25 \times 10^{-2} Wb/m^2$

$ \in = (1.25 \times 10^{-2}) \times (2 \times 10^{-2} ) \times 12 \times \large\frac{1}{2}$

$ \in = 3 \times \large\frac{1}{2} $$\times 10^{-3}$

$\quad= 1.5 \;mv$

Hence d is the correct answer.

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