$\begin{array}{1 1}(a)\;C_2H_2&(b)\;C_6H_6 \\(c)\;C_8H_8&(d)\;C_4H_4\end{array} $

22.414mL of volume at STP is occupied by =0.078g of gaseous hydrocarbon

$\therefore$ 22400mL volume at STP is occupied by =$\large\frac{0.078g}{22.414mL}$$\times 22400mL=78$g gaseous hydrocarbon.

$\therefore$ Molar mass of hydrocarbon=78gmol$^{-1}$

Empirical formula mass of hydrocarbon $CH=12+1=13$

$\therefore n=\large\frac{\text{Molecular mass}}{\text{E.F.mass}}=\frac{78}{13}$$=6$

$\therefore$ Molecular formula of hydrocarbon =$(CH)_6=C_6H_6$

Hence (b) is the correct answer.

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