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A solution contains $1.2046\times 10^{24}$ hydrochloric acid molecules in one $dm^3$ of the solution.The strength of the solution is

$\begin{array}{1 1}(a)\;6N& (b)\;2N \\(c)\;4N&(d)\;8N\end{array}$

$6.023\times 10^{23}$ molecules =1mol of hydrogen
$\therefore$ $1.2046\times 10^{24}$ molecules =$\large\frac{1.2046\times 10^{24}}{6.023\times 10^{23}}$
$\Rightarrow 2$mol
Normality of the solution =2N
Hence (b) is the correct answer.