$\begin{array}{1 1}(a)\;0.56,0.0099& (b)\;0.60,0.0999 \\(c)\;0.0099,0.56&(d)\;0.54,0.1999\end{array} $

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(i) Weight of sugar syrup =214.2g

Weight of sugar in syrup=34.2g

$\therefore$ Weight of water in sugar syrup=(214.2-34.2)g

$\Rightarrow 180.0g$

Molecular weight of sugar=$(C_{12}H_{22}O_{11})$=342

$\therefore$ Molal concentration =$\large\frac{34.2\times 1000}{342\times 180}$$=0.56$

(ii) Mole fraction of sugar

$\large\frac{34.2/342}{(180/18)+(34.2/342)}$

(Mol.wt of water=18)

$\Rightarrow \large\frac{0.1}{10+0.1}=\frac{0.1}{10.1}$$=0.0099$

Hence (a) 0.56,0.0099 is the correct option.

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