Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

A sugar syrup of weight 214.2g contains 34.2g of sugar ($C_{12}H_{22}O_{11})$. Calculate (i) Molal concentration and (ii) Mole fraction of sugar in the syrup.

$\begin{array}{1 1}(a)\;0.56,0.0099& (b)\;0.60,0.0999 \\(c)\;0.0099,0.56&(d)\;0.54,0.1999\end{array} $

Can you answer this question?

1 Answer

0 votes
(i) Weight of sugar syrup =214.2g
Weight of sugar in syrup=34.2g
$\therefore$ Weight of water in sugar syrup=(214.2-34.2)g
$\Rightarrow 180.0g$
Molecular weight of sugar=$(C_{12}H_{22}O_{11})$=342
$\therefore$ Molal concentration =$\large\frac{34.2\times 1000}{342\times 180}$$=0.56$
(ii) Mole fraction of sugar
(Mol.wt of water=18)
$\Rightarrow \large\frac{0.1}{10+0.1}=\frac{0.1}{10.1}$$=0.0099$
Hence (a) 0.56,0.0099 is the correct option.
answered Mar 26, 2014 by sreemathi.v
Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App