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The percentage of nitrogen in urea is about?

$\begin{array}{1 1}(a)\;46&(b)\;85 \\(c)\;18&(d)\;28\end{array} $

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$NH_2CONH_2$ contains 2N
Molecular weight of urea=60g
$\therefore$ % of N=$\large\frac{28}{60}$$\times 100$=46%
Hence (a) is the correct answer.
answered Mar 26, 2014 by sreemathi.v
 

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