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# The specific heat of a metal is 0.16, its approximate atomic weight would be

$\begin{array}{1 1}(a)\;32& (b)\;16 \\(c)\;64&(d)\;40\end{array}$

• The modern form the Dulong–Petit law is : $\large cM = 3R$
$\large\frac{6.4}{\text{specific heat}}$=Atomic weight
Atomic Weight = $\large\frac{6.4}{0.16}$
$\Rightarrow 40$