$(a)\;271 \overset{\circ}{A}\qquad(b)\;282 \overset{\circ}{A}\qquad(c)\;2.71 \overset{\circ}{A}\qquad(d)\;0.27 \overset{\circ}{A}$

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b = $4\times$ Volume occupied by the molecules in one mole of gas.

$= 4\times N\times(\large\frac{4}{3}\pi r^3)$

$r = [\large\frac{3\times24}{16\times(\large\frac{22}{7})\times6.023\times10^{23}}]$

$=1.355\times10^{-8}$cm

$d = 2\times r$

$= 2\times1.355\times10^{-8}$cm

$=2.71\overset{\circ}{A}$

Hence answer is (C)

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