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Which one of the following structures is expected to have three bond pairs and one lone pair?

$\begin{array}{1 1}(a)\;\text{Tetrahedral}& (b)\;\text{Trigonal planar} \\(c)\;\text{Trigonal bipyramidal}&(d)\;\text{Pyramidal}\end{array} $

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As total number of electron pairs are four (3B.P+1L.P),$\therefore$ it exhibits $SP^3$ hybrid state,but due to the presence of one lone pair of electrons it has pyramidal geometry instead of tetrahedral structure.
Hence (d) is the correct answer.
answered Mar 26, 2014 by sreemathi.v

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