logo

Ask Questions, Get Answers

X
 

The bond length in the species $O_2,O_2^+$ and $O_2^-$ are in the order

$\begin{array}{1 1}(a)\;O_2^+ > O_2 > O_2^-\\ (b)\;O_2^+ > O_2^- > O_2 \\(c)\;O_2 > O_2^+ > O_2^-\\(d)\;O_2^- > O_2 > O_2^+\end{array} $

1 Answer

B.O.in $O_2^+=\large\frac{(10-5)}{2}$$=2.5$
B.O.in $O_2=\large\frac{(10-6)}{2}$$=2.0$
B.O.in $O_2^-=\large\frac{(10-7)}{2}$$=1.5$
Higher the bond order,smaller is the bond length.
Hence (d) $O_2^- > O_2 > O_2^+$ is the correct answer.
answered Mar 26, 2014 by sreemathi.v
 

Related questions

...