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Treatment of (+)- glucose with $HIO_4$ gives the results that confirm its aldohexose structure. How many moles of $HIO_4$ should be consumed?

$\begin{array}{1 1}(a)\;3&(b)\;4\\(c)\;5&(d)\;6\end{array} $

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Since in glucose there are five -OH groups so five moles of $HIO_4$ are consumed giving main product formic acid and formaldehyde as shown below:
Glucose + $HIO_4 → 5HCOOH + HCHO$
Hence (c) is the correct answer.
answered Mar 26, 2014 by sreemathi.v

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