Cellulose on hydrolysis with dilute sulphuric acid,gives

$\begin{array}{1 1}(a)\;\alpha-D\text{ glucose}\\(b)\;\beta-D\text{ glucose}\\(c)\;D-\text{fructose}\\(d)\;\text{None}\end{array}$

$(C_6H_{10}O_5)_n + nH_2O → nC_6H_{12}O_6$
Hence (b) is the correct answer.