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Cellulose on hydrolysis with dilute sulphuric acid,gives

$\begin{array}{1 1}(a)\;\alpha-D\text{ glucose}\\(b)\;\beta-D\text{ glucose}\\(c)\;D-\text{fructose}\\(d)\;\text{None}\end{array} $

1 Answer

$(C_6H_{10}O_5)_n + nH_2O → nC_6H_{12}O_6$
Hence (b) is the correct answer.
answered Mar 26, 2014 by sreemathi.v
 

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