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If sucrose is treated with concentrated sulphuric acid, the product formed is

$\begin{array}{1 1}(a)\;CO_2&\\(b)\;C\\(c)\;CH_4\\(d)\;CO\end{array} $

1 Answer

$C_{12} H_{22} O_{11} →12C+11H_2O$
Hence (b) is the correct answer.
answered Mar 26, 2014 by sreemathi.v
 

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