# If sucrose is treated with concentrated sulphuric acid, the product formed is

$\begin{array}{1 1}(a)\;CO_2&\\(b)\;C\\(c)\;CH_4\\(d)\;CO\end{array}$

$C_{12} H_{22} O_{11} →12C+11H_2O$
Hence (b) is the correct answer.
answered Mar 26, 2014