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# $\begin{array}{1 1}\text{statement 1- D Glucopyranose is a non-reducing sugar}\\\text{statement 2- Six membered pyranose ring is always in equalibrium with its open chain counterpart}\end{array}$

$\begin{array}{1 1}(a)\;\text{Statement -1 is True, Statement-2 is True ; Statement -2 is a correct explanation for statement-1}\\(b)\;\text{Statement -1 is True, Statement-2 is True ; Statement -2 is NOT a correct explanation for statement-1}\\(c)\;\text{Statement -1 is True, Statement-2 is false}\\(d)\;\text{Statement -1 is False, Statement-2 is True}\end{array}$

Can you answer this question?

Statement -1 is True, Statement-2 is True ; Statement -2 is a correct explanation for statement-1
Hence (a) is the correct answer.
answered Mar 26, 2014