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Calculate how much of the $\alpha$ and $\beta$ anomers of glucose are present in equlibrium mixture with a specific rotation of 52.6 degrees. (pure $\alpha$ D- glucose has specific rotation = + 112.2 degrees and that of $\beta$- D-glucose has specific rotation + 19 degrees)

$\begin{array}{1 1}(a)\;\text{36 and 64 percentage}\\(b)\;\text{30 and 70 percentage}\\(c)\;\text{40 and 60 percentage}\\(d)\;\text{20 and 74 percentage}\end{array} $

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