# Figure shows graphs of pressure Vs density for an ideal gas at two temperatures $\;T_{1}\;$ and $\;T_{2}\;$

$(a)\;T_{1} > T_{2}\qquad(b)\;T_{1} = T_{2}\qquad(c)\;T_{1} < T_{2}\qquad(d)\;any\;of\;the\;three\;is\;possible$

Answer : $\;T_{1} > T_{2}$
Explanation :
$\large\frac{p}{\rho} = constant = \large\frac{3RT}{M}\;$ (at given temperature)
Greater slope for a higher temperature
answered Mar 27, 2014 by