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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Kinetic Theory of Gases

Figure shows graphs of pressure Vs density for an ideal gas at two temperatures $\;T_{1}\;$ and $\;T_{2}\;$

$(a)\;T_{1} > T_{2}\qquad(b)\;T_{1} = T_{2}\qquad(c)\;T_{1} < T_{2}\qquad(d)\;any\;of\;the\;three\;is\;possible$

1 Answer

Answer : $\;T_{1} > T_{2}$
Explanation :
$\large\frac{p}{\rho} = constant = \large\frac{3RT}{M}\;$ (at given temperature)
Greater slope for a higher temperature
answered Mar 27, 2014 by yamini.v
 

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