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A circular loop of radius R, carrying current I lies in $X-Y $ plane with its centre at origin. The total magnetic flux through $X-Y$ plane is

$(a)\;\text{directly proportional to I } \\(b)\;\text{directly proportional to R} \\ (c)\;\text{directly proportional to $I^2$} \\ (d)\;\text{zero} $

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1 Answer

A circular loop behaves like a dipole with one surface North pole and One surface south pole.
The lines force emerges from N and will meet at S
So net flux through $X-Y$ plane is zero.
Hence d is the correct answer.
answered Mar 27, 2014 by meena.p

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