logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class12  >>  Alternating Current
0 votes

In an LCR series circuit, connected to a source E is at resonance then

$(a)\;\text{voltage across R is zero} \\(b)\;\text {the voltage across R equals applied voltage} \\ (c)\;\text{voltage across C is zero} \\ (d)\;\text{the voltage across C equals applied volage} $

Can you answer this question?
 
 

1 Answer

0 votes
Current in LCR circuit is
$I= \large\frac{E}{\sqrt {R^2 +(wl-\frac{1}{wl})^2}}$
at resonance I is maximum when
$wl -\large\frac{1}{wl} $$=0$
$E=IR$
=voltage across R
Hence b is the correct answer.
answered Mar 27, 2014 by meena.p
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...