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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class12  >>  Alternating Current

In an LCR series circuit, connected to a source E is at resonance then

$(a)\;\text{voltage across R is zero} \\(b)\;\text {the voltage across R equals applied voltage} \\ (c)\;\text{voltage across C is zero} \\ (d)\;\text{the voltage across C equals applied volage} $

1 Answer

Current in LCR circuit is
$I= \large\frac{E}{\sqrt {R^2 +(wl-\frac{1}{wl})^2}}$
at resonance I is maximum when
$wl -\large\frac{1}{wl} $$=0$
$E=IR$
=voltage across R
Hence b is the correct answer.
answered Mar 27, 2014 by meena.p
 

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