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# Resonance frequency of a circuit is f. If capacitance is made 4 time the initial value, the resonance frequency will be

$(a)\;\text{halfed} \\(b)\;\text{double} \\ (c)\;\text{will remain same} \\ (d)\;\text{will be three lines}$

$f= \large\frac{1}{2 \pi \sqrt {LC}}$
$f \alpha \large\frac{1}{\sqrt C}$
$\therefore f$ will become $\large\frac{1}{\sqrt 4}\;$ time
ie f will become $\large\frac{1}{2}$ times
Hence a is the correct answer.

edited Sep 24, 2014