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Questions  >>  JEEMAIN and NEET  >>  Physics  >>  Class12  >>  Alternating Current
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Q)

If $L= 10\;mH,C=100\;\mu F,R=100 \;\Omega $ in a LCR circuit the value of resonance frequency is

$(a)\;\frac{10^3}{2 \pi}Hz \\(b)\;2 \times 10^{3} \; Hz \\ (c)\;\frac{2 \times 10^3}{\pi}\;Hz \\ (d)\;10^3\;Hz $

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