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# The number of particles in a cubic millimeter of a gas at temperature 273 K and 1.00 atm pressure is

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Answer : 2.69 $\times$ 10$^{16}$
$PV = nRT \rightarrow n = \large\frac{PV}{RT}$
Number of particles $= nN_A =\large\frac{PV}{RT}$$N_A = \large\frac{1 \times 1.013 \times 10^5 \times 1 \times 10^{-9} \times 6.02 \times 10^{23}}{8.315 \times 273}$$ = 2.69\times 10^{16}$
answered Mar 27, 2014 by
edited Aug 9, 2014