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A monoatomic gas expands at constant pressure on heating . The percentage of heat supplied used for external work is

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Answer: 40%
For an isobaric process, $Q = nC_P \Delta T$ and $W = nR \Delta T$
Now, $C_P = \large\frac{\gamma R}{ \gamma -1}$ for an isobaric process, where $\gamma$ is the adiabatic index or the heat capacity ratio.
$\Rightarrow \large\frac{\Delta W}{\Delta Q}$$ = \large\frac{R}{C_P}$$ =\large\frac{\gamma -1}{\gamma}$
For monatomic gases, $\gamma = \large\frac{5}{3}$
$\Rightarrow \large\frac{\Delta W}{\Delta Q}$$ =\large\frac{\gamma -1}{\gamma}$$ = \Large\frac{\frac{5}{3}-1}{\frac{5}{3}}$$ = 0.4 = 40\%$
This is the fraction of heat supplied for external work.
answered Mar 27, 2014 by yamini.v
edited Aug 9, 2014 by balaji.thirumalai

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