Email
Chat with tutor
logo

Ask Questions, Get Answers

X
 
Answer
Comment
Share
Q)

Calculate the molality of 1 litre solution of $93 \ % H_2SO_4 $ (weight / volume). the density of the solution is $1.84\;g/ml$.

$(a)\;10.45 \\ (b)\;10.44 \\(c)\;10.43 \\(d)\;10.42 $

1 Answer

Comment
A)
Mass of $H_2SO_4$ in $100\;ml$ (of $93 % \; H_2SO_4 $ )=$93 \;g$
So mass of $H_2SO_4$ in $1000\;ml(IL)$ solution.
$\qquad= \large\frac{93}{100}$$ \times 1000$
$\qquad= 930\;g$
Mass of $1000\; ml \; H_2SO_4$ Solution =volume $\times$ density
$\qquad= 1000 \times 1.84=1840\;g$
Hence mass of water in $1000\;ml\;H_2SO_4$ solution
$\qquad=(1840-930)g=910\;g$
Moles of $H_2SO_4=\large\frac{930}{98}$
Moles of $H_2SO_4$ in $1\;kg$ of water =$\large\frac{930}{98} \times \large\frac{1000}{910}$
$\qquad=10.43\;moles$
Hence molality of solution $=10.43$
Hence c is the correct answer.
Help Clay6 to be free
Clay6 needs your help to survive. We have roughly 7 lakh students visiting us monthly. We want to keep our services free and improve with prompt help and advanced solutions by adding more teachers and infrastructure.

A small donation from you will help us reach that goal faster. Talk to your parents, teachers and school and spread the word about clay6. You can pay online or send a cheque.

Thanks for your support.
Continue
Please choose your payment mode to continue
Home Ask Homework Questions
Your payment for is successful.
Continue
Clay6 tutors use Telegram* chat app to help students with their questions and doubts.
Do you have the Telegram chat app installed?
Already installed Install now
*Telegram is a chat app like WhatsApp / Facebook Messenger / Skype.
...