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Atomic and molecular sizes are of the order of a few Angstrom (1 $\overset{\circ}{A} = 10^{-10}m)$ . Assuming that $N_2$ molecules is spherical in shape with radius $2\times10^{-10}m$ . Calculate the volume of single $N_2$ molecule.

$\begin {array} {1 1}(a)\;3.35\times10^{-23}cm^3\\(b)\;3.35\times10^{-4}cm^3\\(c)\;3.35\times10^{-5}cm^3\\(d)\;3.35\times10^{-19}cm^3\end {array}$

1 Answer

The Volume of the sphere = $\large\frac{4}{3}\pi r^3$
Thus volume of one $N_2$ molecule $=\large\frac{4}{3}\times\large\frac{22}{7}\times(2\times10^{-10})^3m^3$
$= 3.35\times10^{-23}cm^3$
Hence answer (A)
answered Mar 28, 2014 by sharmaaparna1

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