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Calculate the molarity of water if its density is $1000 kg/m^3$

$(a)\;55.55\;M \\ (b)\;54.55\;M \\(c)\;55.45\;M \\(d)\;55.54 \;M $

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A)
1 liter water =1 kg
or 1000 ml water =1 kg [Given $d= 1000 kg/m^3$]
Moles of water present in $1000 ml = \large\frac{1000}{18}$$=55.55$
Hence molarity of water $=55.55 \;M$
Hence a is the correct answer.
ye 1000 upon 18 kaise aya plzz tell me in detail
Mass=density×volume=1×1000 and dividing by 18(molecular mass) gives moles
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