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Home  >>  CBSE XI  >>  Math  >>  Sequences and Series
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If the sum of three numbers in A.P. is $24$ and their product is $440$, then find the numbers.

$\begin{array}{1 1}3,5,7 \\ 5,8,11 \\ 5,7,9 \\ 3,7,11 \end{array} $

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  • Three numbers in A.P. are to be assumed as $a-d,\:a,\:a+d$
Let the three numbers in A.P. be $a-d,\:a,\:a+d$
Given that the sum of the numbers $=24$
$\Rightarrow\:3a=24$ or $a=8$
Also given that the product of the numbers $=440$
Substituting the value of $a$ we get
$\Rightarrow\:d^2=64-55=9$ or $d=\pm3$
Substituting the value of $a$ and $d$ we get the three numbers are
answered Mar 28, 2014 by rvidyagovindarajan_1

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