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# The unit $J\; Pa^{-1}$ is equivalent to

$(a)\;m^3 \\ (b)\;cm^3 \\(c)\;dm^3 \\(d)\;none\; of\; these$

$1 \;J\; Pa^{-1} =\large\frac{1 \;J}{1\;Pa}$
$\qquad= \large\frac{energy}{pressure}$
$\qquad = \large\frac{force \times distance}{force /area}$
$\qquad= area \times distance =m^2.m=m^3$