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# The charge on 1 gram ion of $Al^{3+}$ is :

$(a)\;\frac{1}{29} \times 96500\;coulomb \\ (b)\;\frac{1}{3} \times 96500 \;coulomb \\(c)\; \frac{1}{9} \times 96500\;coulomb \\(d)\;3 \times 96500 \;coulomb$

Charge on one mole of electrons $= 6.023 \times 10^{23} \times 1.6 \times 10^{-19}\;C$
$\qquad= 96500\;coulomb$
1 gram ions means 1 mole
Charge on 1 mole of $Al^{3+}\;ion= 3 \times 96500\; coulomb$
Hence d is the correct answer.