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A gas at $0^{\large\circ}C$ and 1 atm pressure occupies 2.5 litre . What change in temperature would be necessary if the pressure is to be adjusted to 1.5 atm and the gas has been transferred to a 2.0 litre container?

$(a)\;546^{\large\circ}C\qquad(b)\;54.6^{\large\circ}C\qquad(c)\;300K\qquad(d)\;50^{\large\circ}C$

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Given
$P_1 = 1 atm$
$V_1$ = 2.5 litre
$T_1$ = 273K
$P_2$ = 1.5 atm
$V_2$ = 2.0 litre
$T_2$ = ?
We know that
$\large\frac{P_1V_1}{T_1} = \large\frac{P_2V_2}{T_2}$
$\large\frac{1\times2.5}{273} = \large\frac{1.5\times2.0}{T_2}$
$\Rightarrow T_2 = 327.6 K$
$\Rightarrow or \;\;54.6^{\large\circ}C$
Hence answer is (B)
answered Mar 29, 2014 by sharmaaparna1
 

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