$(a)\;546^{\large\circ}C\qquad(b)\;54.6^{\large\circ}C\qquad(c)\;300K\qquad(d)\;50^{\large\circ}C$

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Given

$P_1 = 1 atm$

$V_1$ = 2.5 litre

$T_1$ = 273K

$P_2$ = 1.5 atm

$V_2$ = 2.0 litre

$T_2$ = ?

We know that

$\large\frac{P_1V_1}{T_1} = \large\frac{P_2V_2}{T_2}$

$\large\frac{1\times2.5}{273} = \large\frac{1.5\times2.0}{T_2}$

$\Rightarrow T_2 = 327.6 K$

$\Rightarrow or \;\;54.6^{\large\circ}C$

Hence answer is (B)

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