$(a)\;1.48 \;atm\qquad(b)\;0.148\;atm\qquad(c)\;15.828\;atm\qquad(d)\;None\;of\;these$

Given

w = 20g dry $CO_2$ which will evaporate to develop P

m = 44

V = 0.75 litre

P = ?

T = 298 K

PV = $\large\frac{w}{m} RT$

$P\times 0.75 = \large\frac{20}{44}\times0.0821\times298$

$\Rightarrow$ P = 14.828 atm

Pressure inside bottle = P + atm. pressure

$\Rightarrow$ 14.828 + 1 = 15.828 atm

Hence answer is (C)

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