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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Kinetic Theory of Gases
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At what temperature the molecule of nitrogen will have the same rms velocity as the molecule of oxygen at $\;127^{0}C\;$ ?


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Answer : $\;457^{0}C$
Explanation :
$\large\frac{V_{N_{2}}}{V_{O_{2}}} = 1$
$\sqrt{\large\frac{3RT_{1}}{M_{N_{2}}}} = \sqrt{\large\frac{3RT_{2}}{M_{O_{2}}}}$
$T_{1} = T_{2} \times \large\frac{M_{N_{2}}}{M_{O_{2}}}$
$= \large\frac{400 \times 28}{32} = 350 K$
Therefore , $\;t=350 - 273 =77^{0}C $
answered Mar 31, 2014 by yamini.v

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