$[P + \large\frac{a}{V^2}][V-b] = RT$
b is negligible
$\therefore PV + \large\frac{a}{V} = RT$
(or) $V^2P - RTV + a = 0$
$V = + RT \pm \large\frac{\sqrt{R^2T^2 - 4aP}}{2P}$
Since V has only one value
$R^2T^2 = 4aP$
$P = \large\frac{R^2T^2}{4a}$
$=\large\frac{{0.0821}^2\times273\times273}{4\times3.592}$
= 34.96 atm
Hence answer is (C)