Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

A vessel has nitrogen gas and water vapour at a total pressure of 1 atm . The partial pressure of water vapour is 0.3 atm. When the contents of this vessel are transformed to another vessel having one third of the capacity of original vessel , completely at the same temperature , the total pressure of the system in the new vessel is:

$(a)\;3.0 atm\qquad(b)\;1 atm\qquad(c)\;3.33 atm\qquad(d)\;2.4 atm$

Can you answer this question?

1 Answer

0 votes
$P_{N_2} + P_{H_2O} = 1 atm$
$\therefore P_{H_2O} = 0.3\;atm$
$\therefore P_{N_2}$ = 0.7 atm in 1 vessel .
Now new pressure of $N_2$ in another vessel may be calculated as
$P_1V_1 = P_2V_2$
$\therefore 0.7 \times V_1 = P_2\times \large\frac{V_1}{3}$atm
$\therefore P_{N_2}$ = 2.1 atm
$\Rightarrow P_{H_2O} = 0.3$atm
$P_T = 2.4$ atm
$P_{H_2O}$ remains constant at constant temperature
Hence answer is (D)
answered Mar 31, 2014 by sharmaaparna1

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App