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Which of the following has the largest number of atoms?

$(a)\;0.5\;g\;atoms\;of\;Cu \\ (b)\;0.635\;g\;Cu \\(c)\;0.25\;g \;moles \;of \;Cu\;atoms \\(d)\;1\;g\;of\;Cu $
Can you answer this question?

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$0.5$ g atoms cu= $0.5 \times 6.023 \times 10^{23}$
$\qquad= 3.0115 \times 10^{3}\;cu\;atom$
$0.635\;g cu=\large\frac{0.635}{63.5}$$ \times 6.023 \times 10^{23}$
$\qquad=6.023 \times 10^{21}\;cu\;atoms$
$0.25$ mole $cu=0.25 \times 6.023 \times 10^{23}$
$\qquad= 1.5 \times 10^{23} \;cu\;atom$
$1 \;g Cu =\large\frac{1}{63.5} $$ \times 6.023 \times 10^{23}$
$\qquad= 9.48 \times 10^{21}\;cu\;atom$
Hence a is the correct answer.
answered Mar 31, 2014 by meena.p
edited Mar 31, 2014 by meena.p

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