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The density of salt solution is $1.13\;g\;cm^{-3}$ at $298\;k$. The solution contains $17.0 \%$ sodium chloride . What volume of solution will contain $38.42 \;g$ of $NaCl$?

$(a)\;255.38\;cm^3 \\ (b)\;200\;cm^3 \\(c)\;578\;cm^3 \\(d)\;226\;cm^3 $
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Suppose mass of solution $=xg$
$\therefore 17.0 \%$ of $x =38.42 g$ or $\large\frac{17}{100} $$ \times x =38.42\;g$
or $\large\frac{17}{100}$$ \times x =38.42 \;g$
$x=\large\frac{38.42 \times 100}{17}$$=226\;g$
Now volume $=\large\frac{mass}{densaity}$
$\therefore V =\large\frac{226\;g}{1.13\;g}$
$\qquad= 200\;cm^3$
Hence b is the correct answer.
answered Apr 1, 2014 by meena.p
 

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