$(a)\;817mm\;of\;Hg\qquad(b)\;8.17mm\;of\;Hg\qquad(c)\;817cm\;of\;Hg\qquad(d)\;8.17 \;litre$

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At 'T' K

$P_{gas} = P_{dry gas} + P_{moisture}$

$P_{dry gas} = 830 - 30$

$\;\;\;\;\;\;\;\;\;\;\;= 800 mm$

Now at new temperature $T_1 = T - \large\frac{T}{100}$

$\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\; = 0.99 T$

Since $V_1 = V_2 \large\frac{P}{T}$ = constant

$P_{dry gas} = \large\frac{800\times0.99T}{T}$

$\;\;\;\;\;\;\;\;\;\;\;\;\;\; =792 mm$

$P_{gas} = P_{dry gas}+P_{moisture}$

$\;\;\;\;\;\;\;\;\;=792 + 25$

$\;\;\;\;\;\;\;\;\;\;\;= 817 \;mm\;of\;Hg$

Hence answer is (A)

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